(-3+1)^2+(3+-5)^2=r

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Solution for (-3+1)^2+(3+-5)^2=r equation: 



(-3+1)^2+(3+-5)^2=r

We move all terms to the left:

(-3+1)^2+(3+-5)^2-(r)=0

We add all the numbers together, and all the variables

-r+(-2)^2+(-2)^2=0

We add all the numbers together, and all the variables

-1r+8=0

We move all terms containing r to the left, all other terms to the right

-r=-8

r=-8/-1

r=+8

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